"A stone is thrown in a vertically upward direction with a velocity of 5m/s. If the acceleration of the stone during its motion is 10m/s^2 in the downward direction , what will be the height attained by the stone and how much time will it take to reach there?"Answer: Take, u=5m/s a= -10 m/s2 v=0 at the topmost position S= Hmax = ? The eqn of motion to use v2 - u2 = 2aS Which gives H = 1.25 m From the eqn v=u + at t= 0.5 s
A question from kinematics - motion in one dimension
Natasha Sehgal Asked:
